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2016-9-1 11:51 |
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签到天数: 38 天 [LV.5]常住居民I
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发表于 2008-8-17 02:32:48
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新版本的都改过了，老版不管用了，想想看等您这套出来的话，人家开店的人电脑早没有用了，以前的延期加密算法本人截取部分列出：“select @ls_str_b1 = right(convert(varchar,convert(integer,substring(@ls_tmp_str,35,1)) + 10 - 7),1), @ls_str_b2 = right(convert(varchar,convert(integer,substring(@ls_tmp_str,44,1)) + 10 - 8),1), @ls_str_b3 = right(convert(varchar,convert(integer,substring(@ls_tmp_str,27,1)) + 10 - 6),1) select @ls_str_a1 = (case when f.a1 = '8' then '0' when f.a1 = '7' then '1' when f.a1 = '6' then '2' when f.a1 = '5' then '3' end), @ls_str_a2 = (case when f.a2 = '1' then '0' when f.a2 = '0' then '1' when f.a2 = '/' then '2' when f.a2 = '.' then '3' when f.a2 = '-' then '4' when f.a2 = ',' then '5' when f.a2 = '+' then '6' when f.a2 = '*' then '7' when f.a2 = ')' then '8' when f.a2 = '(' then '9' end), @ls_str_a3 = (case when f.a3 = 'A' then '0' when f.a3 = [email=]'@'[/email] then '1' when f.a3 = '?' then '2' when f.a3 = '>' then '3' when f.a3 = '=' then '4' when f.a3 = '<' then '5' when f.a3 = ';' then '6' when f.a3 = ':' then '7' when f.a3 = '9' then '8' when f.a3 = '8' then '9' end) from (select substring(system_value,len(system_value) - 1,1) as a1, substring(system_value,len(system_value),1) as a2, substring(system_value,len(system_value) - 3,1) as a3 from sys_option where system_id = 'RUN_FIRST_DATE') as f if(@ls_str_b1 = @ls_str_a1 and @ls_str_b2 = @ls_str_a2 and @ls_str_b3 = @ls_str_a3) GoTo Rigth_End select @ai_rtn = -1 Return Rigth_End: select @ai_rtn = 0 Return end ”
这些现都没有用了，不多说了，献丑了，呵呵 |
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